c^2-3c=27c+3c

Solution for c^2-3c=27c+3c equation:

c^2-3c=27c+3c

We move all terms to the left:

c^2-3c-(27c+3c)=0

We add all the numbers together, and all the variables

c^2-3c-(+30c)=0

We get rid of parentheses

c^2-3c-30c=0

We add all the numbers together, and all the variables

c^2-33c=0

a = 1; b = -33; c = 0;
Δ = b2-4ac
Δ = -332-4·1·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-33}{2*1}=\frac{0}{2}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+33}{2*1}=\frac{66}{2}
=33
$